Integrand size = 34, antiderivative size = 142 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {1}{8} a (5 A-2 B) c^3 x+\frac {a (5 A-2 B) c^3 \cos ^3(e+f x)}{12 f}+\frac {a (5 A-2 B) c^3 \cos (e+f x) \sin (e+f x)}{8 f}-\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f} \]
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Time = 0.17 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {3046, 2939, 2757, 2748, 2715, 8} \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {a c^3 (5 A-2 B) \cos ^3(e+f x)}{12 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f}+\frac {a c^3 (5 A-2 B) \sin (e+f x) \cos (e+f x)}{8 f}+\frac {1}{8} a c^3 x (5 A-2 B)-\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f} \]
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Rule 8
Rule 2715
Rule 2748
Rule 2757
Rule 2939
Rule 3046
Rubi steps \begin{align*} \text {integral}& = (a c) \int \cos ^2(e+f x) (A+B \sin (e+f x)) (c-c \sin (e+f x))^2 \, dx \\ & = -\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {1}{5} (a (5 A-2 B) c) \int \cos ^2(e+f x) (c-c \sin (e+f x))^2 \, dx \\ & = -\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f}+\frac {1}{4} \left (a (5 A-2 B) c^2\right ) \int \cos ^2(e+f x) (c-c \sin (e+f x)) \, dx \\ & = \frac {a (5 A-2 B) c^3 \cos ^3(e+f x)}{12 f}-\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f}+\frac {1}{4} \left (a (5 A-2 B) c^3\right ) \int \cos ^2(e+f x) \, dx \\ & = \frac {a (5 A-2 B) c^3 \cos ^3(e+f x)}{12 f}+\frac {a (5 A-2 B) c^3 \cos (e+f x) \sin (e+f x)}{8 f}-\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f}+\frac {1}{8} \left (a (5 A-2 B) c^3\right ) \int 1 \, dx \\ & = \frac {1}{8} a (5 A-2 B) c^3 x+\frac {a (5 A-2 B) c^3 \cos ^3(e+f x)}{12 f}+\frac {a (5 A-2 B) c^3 \cos (e+f x) \sin (e+f x)}{8 f}-\frac {a B c \cos ^3(e+f x) (c-c \sin (e+f x))^2}{5 f}+\frac {a (5 A-2 B) \cos ^3(e+f x) \left (c^3-c^3 \sin (e+f x)\right )}{20 f} \\ \end{align*}
Time = 1.28 (sec) , antiderivative size = 123, normalized size of antiderivative = 0.87 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {a c^3 \cos (e+f x) \left (80 A-56 B-\frac {30 (5 A-2 B) \arcsin \left (\frac {\sqrt {1-\sin (e+f x)}}{\sqrt {2}}\right )}{\sqrt {\cos ^2(e+f x)}}+15 (3 A+2 B) \sin (e+f x)+(-80 A+32 B) \sin ^2(e+f x)+30 (A-2 B) \sin ^3(e+f x)+24 B \sin ^4(e+f x)\right )}{120 f} \]
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Time = 1.50 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.69
method | result | size |
parallelrisch | \(\frac {\left (\left (\frac {2 A}{3}-\frac {5 B}{12}\right ) \cos \left (3 f x +3 e \right )+\left (-\frac {A}{8}+\frac {B}{4}\right ) \sin \left (4 f x +4 e \right )+\frac {\cos \left (5 f x +5 e \right ) B}{20}+A \sin \left (2 f x +2 e \right )+\left (2 A -\frac {3 B}{2}\right ) \cos \left (f x +e \right )+\frac {5 f x A}{2}-f x B +\frac {8 A}{3}-\frac {28 B}{15}\right ) c^{3} a}{4 f}\) | \(98\) |
risch | \(\frac {5 a \,c^{3} x A}{8}-\frac {a \,c^{3} x B}{4}+\frac {c^{3} a \cos \left (f x +e \right ) A}{2 f}-\frac {3 c^{3} a \cos \left (f x +e \right ) B}{8 f}+\frac {B a \,c^{3} \cos \left (5 f x +5 e \right )}{80 f}-\frac {\sin \left (4 f x +4 e \right ) A \,c^{3} a}{32 f}+\frac {\sin \left (4 f x +4 e \right ) B \,c^{3} a}{16 f}+\frac {c^{3} a \cos \left (3 f x +3 e \right ) A}{6 f}-\frac {5 c^{3} a \cos \left (3 f x +3 e \right ) B}{48 f}+\frac {A \,c^{3} a \sin \left (2 f x +2 e \right )}{4 f}\) | \(164\) |
parts | \(-\frac {\left (-2 A \,c^{3} a +B \,c^{3} a \right ) \cos \left (f x +e \right )}{f}+\frac {\left (-A \,c^{3} a +2 B \,c^{3} a \right ) \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f}+a \,c^{3} x A -\frac {2 A \,c^{3} a \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3 f}-\frac {2 B \,c^{3} a \left (-\frac {\cos \left (f x +e \right ) \sin \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )}{f}+\frac {B \,c^{3} a \left (\frac {8}{3}+\sin ^{4}\left (f x +e \right )+\frac {4 \left (\sin ^{2}\left (f x +e \right )\right )}{3}\right ) \cos \left (f x +e \right )}{5 f}\) | \(180\) |
derivativedivides | \(\frac {-A \,c^{3} a \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {2 A \,c^{3} a \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+2 A \cos \left (f x +e \right ) a \,c^{3}+\frac {B \,c^{3} a \left (\frac {8}{3}+\sin ^{4}\left (f x +e \right )+\frac {4 \left (\sin ^{2}\left (f x +e \right )\right )}{3}\right ) \cos \left (f x +e \right )}{5}+2 B \,c^{3} a \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-2 B \,c^{3} a \left (-\frac {\cos \left (f x +e \right ) \sin \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )+A \,c^{3} a \left (f x +e \right )-B \cos \left (f x +e \right ) a \,c^{3}}{f}\) | \(208\) |
default | \(\frac {-A \,c^{3} a \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {2 A \,c^{3} a \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+2 A \cos \left (f x +e \right ) a \,c^{3}+\frac {B \,c^{3} a \left (\frac {8}{3}+\sin ^{4}\left (f x +e \right )+\frac {4 \left (\sin ^{2}\left (f x +e \right )\right )}{3}\right ) \cos \left (f x +e \right )}{5}+2 B \,c^{3} a \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-2 B \,c^{3} a \left (-\frac {\cos \left (f x +e \right ) \sin \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )+A \,c^{3} a \left (f x +e \right )-B \cos \left (f x +e \right ) a \,c^{3}}{f}\) | \(208\) |
norman | \(\frac {\left (\frac {5}{8} A \,c^{3} a -\frac {1}{4} B \,c^{3} a \right ) x +\left (\frac {5}{8} A \,c^{3} a -\frac {1}{4} B \,c^{3} a \right ) x \left (\tan ^{10}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (\frac {25}{4} A \,c^{3} a -\frac {5}{2} B \,c^{3} a \right ) x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (\frac {25}{4} A \,c^{3} a -\frac {5}{2} B \,c^{3} a \right ) x \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (\frac {25}{8} A \,c^{3} a -\frac {5}{4} B \,c^{3} a \right ) x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\left (\frac {25}{8} A \,c^{3} a -\frac {5}{4} B \,c^{3} a \right ) x \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {\left (4 A \,c^{3} a -2 B \,c^{3} a \right ) \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {20 A \,c^{3} a -14 B \,c^{3} a}{15 f}+\frac {2 \left (4 A \,c^{3} a -4 B \,c^{3} a \right ) \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f}+\frac {\left (8 A \,c^{3} a -8 B \,c^{3} a \right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{3 f}+\frac {2 \left (8 A \,c^{3} a -2 B \,c^{3} a \right ) \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{3 f}+\frac {c^{3} a \left (3 A +2 B \right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{4 f}-\frac {c^{3} a \left (3 A +2 B \right ) \left (\tan ^{9}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{4 f}+\frac {c^{3} a \left (-6 B +7 A \right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 f}-\frac {c^{3} a \left (-6 B +7 A \right ) \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2 f}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{5}}\) | \(424\) |
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Time = 0.26 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.72 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {24 \, B a c^{3} \cos \left (f x + e\right )^{5} + 80 \, {\left (A - B\right )} a c^{3} \cos \left (f x + e\right )^{3} + 15 \, {\left (5 \, A - 2 \, B\right )} a c^{3} f x - 15 \, {\left (2 \, {\left (A - 2 \, B\right )} a c^{3} \cos \left (f x + e\right )^{3} - {\left (5 \, A - 2 \, B\right )} a c^{3} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{120 \, f} \]
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Leaf count of result is larger than twice the leaf count of optimal. 486 vs. \(2 (129) = 258\).
Time = 0.30 (sec) , antiderivative size = 486, normalized size of antiderivative = 3.42 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\begin {cases} - \frac {3 A a c^{3} x \sin ^{4}{\left (e + f x \right )}}{8} - \frac {3 A a c^{3} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} - \frac {3 A a c^{3} x \cos ^{4}{\left (e + f x \right )}}{8} + A a c^{3} x + \frac {5 A a c^{3} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {2 A a c^{3} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} + \frac {3 A a c^{3} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} - \frac {4 A a c^{3} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac {2 A a c^{3} \cos {\left (e + f x \right )}}{f} + \frac {3 B a c^{3} x \sin ^{4}{\left (e + f x \right )}}{4} + \frac {3 B a c^{3} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{2} - B a c^{3} x \sin ^{2}{\left (e + f x \right )} + \frac {3 B a c^{3} x \cos ^{4}{\left (e + f x \right )}}{4} - B a c^{3} x \cos ^{2}{\left (e + f x \right )} + \frac {B a c^{3} \sin ^{4}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {5 B a c^{3} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{4 f} + \frac {4 B a c^{3} \sin ^{2}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac {3 B a c^{3} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{4 f} + \frac {B a c^{3} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} + \frac {8 B a c^{3} \cos ^{5}{\left (e + f x \right )}}{15 f} - \frac {B a c^{3} \cos {\left (e + f x \right )}}{f} & \text {for}\: f \neq 0 \\x \left (A + B \sin {\left (e \right )}\right ) \left (a \sin {\left (e \right )} + a\right ) \left (- c \sin {\left (e \right )} + c\right )^{3} & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 200, normalized size of antiderivative = 1.41 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {320 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} A a c^{3} - 15 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} A a c^{3} + 480 \, {\left (f x + e\right )} A a c^{3} + 32 \, {\left (3 \, \cos \left (f x + e\right )^{5} - 10 \, \cos \left (f x + e\right )^{3} + 15 \, \cos \left (f x + e\right )\right )} B a c^{3} + 30 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} B a c^{3} - 240 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} B a c^{3} + 960 \, A a c^{3} \cos \left (f x + e\right ) - 480 \, B a c^{3} \cos \left (f x + e\right )}{480 \, f} \]
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Time = 0.32 (sec) , antiderivative size = 140, normalized size of antiderivative = 0.99 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {B a c^{3} \cos \left (5 \, f x + 5 \, e\right )}{80 \, f} + \frac {A a c^{3} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} + \frac {1}{8} \, {\left (5 \, A a c^{3} - 2 \, B a c^{3}\right )} x + \frac {{\left (8 \, A a c^{3} - 5 \, B a c^{3}\right )} \cos \left (3 \, f x + 3 \, e\right )}{48 \, f} + \frac {{\left (4 \, A a c^{3} - 3 \, B a c^{3}\right )} \cos \left (f x + e\right )}{8 \, f} - \frac {{\left (A a c^{3} - 2 \, B a c^{3}\right )} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} \]
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Time = 14.19 (sec) , antiderivative size = 389, normalized size of antiderivative = 2.74 \[ \int (a+a \sin (e+f x)) (A+B \sin (e+f x)) (c-c \sin (e+f x))^3 \, dx=\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (\frac {3\,A\,a\,c^3}{4}+\frac {B\,a\,c^3}{2}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8\,\left (4\,A\,a\,c^3-2\,B\,a\,c^3\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (\frac {7\,A\,a\,c^3}{2}-3\,B\,a\,c^3\right )-{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\,\left (\frac {7\,A\,a\,c^3}{2}-3\,B\,a\,c^3\right )-{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9\,\left (\frac {3\,A\,a\,c^3}{4}+\frac {B\,a\,c^3}{2}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6\,\left (8\,A\,a\,c^3-8\,B\,a\,c^3\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (\frac {8\,A\,a\,c^3}{3}-\frac {8\,B\,a\,c^3}{3}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (\frac {16\,A\,a\,c^3}{3}-\frac {4\,B\,a\,c^3}{3}\right )+\frac {4\,A\,a\,c^3}{3}-\frac {14\,B\,a\,c^3}{15}}{f\,\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{10}+5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8+10\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+10\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+1\right )}+\frac {a\,c^3\,\mathrm {atan}\left (\frac {a\,c^3\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (5\,A-2\,B\right )}{4\,\left (\frac {5\,A\,a\,c^3}{4}-\frac {B\,a\,c^3}{2}\right )}\right )\,\left (5\,A-2\,B\right )}{4\,f}-\frac {a\,c^3\,\left (5\,A-2\,B\right )\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )-\frac {f\,x}{2}\right )}{4\,f} \]
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